3.421 \(\int (c x)^m (a x^j+b x^n)^{3/2} \, dx\)

Optimal. Leaf size=107 \[ \frac{2 b x^{n+1} (c x)^m \sqrt{a x^j+b x^n} \, _2F_1\left (-\frac{3}{2},\frac{m+\frac{3 n}{2}+1}{j-n};\frac{m+\frac{3 n}{2}+1}{j-n}+1;-\frac{a x^{j-n}}{b}\right )}{(2 m+3 n+2) \sqrt{\frac{a x^{j-n}}{b}+1}} \]

[Out]

(2*b*x^(1 + n)*(c*x)^m*Sqrt[a*x^j + b*x^n]*Hypergeometric2F1[-3/2, (1 + m + (3*n)/2)/(j - n), 1 + (1 + m + (3*
n)/2)/(j - n), -((a*x^(j - n))/b)])/((2 + 2*m + 3*n)*Sqrt[1 + (a*x^(j - n))/b])

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Rubi [A]  time = 0.102115, antiderivative size = 107, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {2032, 365, 364} \[ \frac{2 b x^{n+1} (c x)^m \sqrt{a x^j+b x^n} \, _2F_1\left (-\frac{3}{2},\frac{m+\frac{3 n}{2}+1}{j-n};\frac{m+\frac{3 n}{2}+1}{j-n}+1;-\frac{a x^{j-n}}{b}\right )}{(2 m+3 n+2) \sqrt{\frac{a x^{j-n}}{b}+1}} \]

Antiderivative was successfully verified.

[In]

Int[(c*x)^m*(a*x^j + b*x^n)^(3/2),x]

[Out]

(2*b*x^(1 + n)*(c*x)^m*Sqrt[a*x^j + b*x^n]*Hypergeometric2F1[-3/2, (1 + m + (3*n)/2)/(j - n), 1 + (1 + m + (3*
n)/2)/(j - n), -((a*x^(j - n))/b)])/((2 + 2*m + 3*n)*Sqrt[1 + (a*x^(j - n))/b])

Rule 2032

Int[((c_.)*(x_))^(m_.)*((a_.)*(x_)^(j_.) + (b_.)*(x_)^(n_.))^(p_), x_Symbol] :> Dist[(c^IntPart[m]*(c*x)^FracP
art[m]*(a*x^j + b*x^n)^FracPart[p])/(x^(FracPart[m] + j*FracPart[p])*(a + b*x^(n - j))^FracPart[p]), Int[x^(m
+ j*p)*(a + b*x^(n - j))^p, x], x] /; FreeQ[{a, b, c, j, m, n, p}, x] &&  !IntegerQ[p] && NeQ[n, j] && PosQ[n
- j]

Rule 365

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a + b*x^n)^FracPart[p])
/(1 + (b*x^n)/a)^FracPart[p], Int[(c*x)^m*(1 + (b*x^n)/a)^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[
p, 0] &&  !(ILtQ[p, 0] || GtQ[a, 0])

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin{align*} \int (c x)^m \left (a x^j+b x^n\right )^{3/2} \, dx &=\frac{\left (x^{-m-\frac{n}{2}} (c x)^m \sqrt{a x^j+b x^n}\right ) \int x^{m+\frac{3 n}{2}} \left (b+a x^{j-n}\right )^{3/2} \, dx}{\sqrt{b+a x^{j-n}}}\\ &=\frac{\left (b x^{-m-\frac{n}{2}} (c x)^m \sqrt{a x^j+b x^n}\right ) \int x^{m+\frac{3 n}{2}} \left (1+\frac{a x^{j-n}}{b}\right )^{3/2} \, dx}{\sqrt{1+\frac{a x^{j-n}}{b}}}\\ &=\frac{2 b x^{1+n} (c x)^m \sqrt{a x^j+b x^n} \, _2F_1\left (-\frac{3}{2},\frac{1+m+\frac{3 n}{2}}{j-n};1+\frac{1+m+\frac{3 n}{2}}{j-n};-\frac{a x^{j-n}}{b}\right )}{(2+2 m+3 n) \sqrt{1+\frac{a x^{j-n}}{b}}}\\ \end{align*}

Mathematica [B]  time = 0.355433, size = 218, normalized size = 2.04 \[ \frac{2 (c x)^m \left (3 a^2 (j-n)^2 x^{2 j+1} \sqrt{\frac{a x^{j-n}}{b}+1} \, _2F_1\left (\frac{1}{2},\frac{4 j+2 m-n+2}{2 j-2 n};\frac{6 j+2 m-3 n+2}{2 j-2 n};-\frac{a x^{j-n}}{b}\right )+x^{-m} (4 j+2 m-n+2) \left (a x^j+b x^n\right ) \left (a (-j+2 m+4 n+2) x^{j+m+1}+b (2 j+2 m+n+2) x^{m+n+1}\right )\right )}{(2 m+3 n+2) (4 j+2 m-n+2) (2 j+2 m+n+2) \sqrt{a x^j+b x^n}} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^m*(a*x^j + b*x^n)^(3/2),x]

[Out]

(2*(c*x)^m*(((2 + 4*j + 2*m - n)*(a*x^j + b*x^n)*(a*(2 - j + 2*m + 4*n)*x^(1 + j + m) + b*(2 + 2*j + 2*m + n)*
x^(1 + m + n)))/x^m + 3*a^2*(j - n)^2*x^(1 + 2*j)*Sqrt[1 + (a*x^(j - n))/b]*Hypergeometric2F1[1/2, (2 + 4*j +
2*m - n)/(2*j - 2*n), (2 + 6*j + 2*m - 3*n)/(2*j - 2*n), -((a*x^(j - n))/b)]))/((2 + 4*j + 2*m - n)*(2 + 2*j +
2*m + n)*(2 + 2*m + 3*n)*Sqrt[a*x^j + b*x^n])

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Maple [F]  time = 0.692, size = 0, normalized size = 0. \begin{align*} \int \left ( cx \right ) ^{m} \left ( a{x}^{j}+b{x}^{n} \right ) ^{{\frac{3}{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^m*(a*x^j+b*x^n)^(3/2),x)

[Out]

int((c*x)^m*(a*x^j+b*x^n)^(3/2),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a x^{j} + b x^{n}\right )}^{\frac{3}{2}} \left (c x\right )^{m}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m*(a*x^j+b*x^n)^(3/2),x, algorithm="maxima")

[Out]

integrate((a*x^j + b*x^n)^(3/2)*(c*x)^m, x)

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Fricas [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m*(a*x^j+b*x^n)^(3/2),x, algorithm="fricas")

[Out]

Exception raised: UnboundLocalError

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**m*(a*x**j+b*x**n)**(3/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a x^{j} + b x^{n}\right )}^{\frac{3}{2}} \left (c x\right )^{m}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^m*(a*x^j+b*x^n)^(3/2),x, algorithm="giac")

[Out]

integrate((a*x^j + b*x^n)^(3/2)*(c*x)^m, x)